(x^2-9)^1/2-x=-3

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Solution for (x^2-9)^1/2-x=-3 equation: 


x in (-oo:+oo)

((x^2-9)^1)/2-x = -3 // + 3

((x^2-9)^1)/2-x+3 = 0

(x^2-9)/2-x+3 = 0

(x^2-9)/2+(2*(-x))/2+(2*3)/2 = 0

x^2+2*(-x)+2*3-9 = 0

x^2-2*x-9+6 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

(x+1)*(x-3) = 0

((x+1)*(x-3))/2 = 0

((x+1)*(x-3))/2 = 0 // * 2

(x+1)*(x-3) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -1, 3 }

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